### Algebra: Calculating with exponents and roots

### Square roots

Square roots

Recall that #\sqrt{\blue {9}} = \orange 3#. \[\orange x^2=\blue a \qquad \text{and} \qquad \orange x\geq 0\] |
\[\begin{array}{c} |

no

We can substitute every value for #x# for which #x+6# is greater than or equal to #0#, since the number below the root sign cannot be negative.

If we substitute #x=-9#, we get #-9+6=-3 \lt 0 #. Hence, we can not substitute this value.

We can substitute every value for #x# for which #x+6# is greater than or equal to #0#, since the number below the root sign cannot be negative.

If we substitute #x=-9#, we get #-9+6=-3 \lt 0 #. Hence, we can not substitute this value.

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