The red dots are the four dots from the question. These are calculated as follows:
The formula is already written in the form of #a \cdot x^2+b \cdot x +c# with #a =-{{1}\over{3}}#, #b=-2# and #c=7#. Seeing as #a<0# the graph is a parabola that opens downward.

The intersection with the #y#-axis is equal to the value of the constant in the quadratic formula, which is equal to #7#. That means that the coordinates of the intersection point with the #y#-axis are #\rv{0,7}#.

The #x#-value of the vertex is given by #x=-\dfrac{b}{2 \cdot a}# and is equal to:
\[\begin{array}{rclrl}
x&=& -\dfrac{-2}{2 \cdot -{{1}\over{3}}} &&\phantom{xxx}\blue{\text{formula entered}}\\
&=& -3 &&\phantom{xxx}\blue{\text{simplified}}\\
\end{array}\]
The #y#-value of the vertex is calculated by entering #x=-3# in the formula. Which gives:
\[\begin{array}{rclrl}
y&=& -{{1}\over{3}} \cdot \left(-3\right)^2 -2 \cdot -3 +7
&&\phantom{xxx}\blue{\text{formula entered}}\\
&=& 10 &&\phantom{xxx}\blue{\text{calculated}}\\
\end{array}\]
The coordinates of the vertex are: #\rv{-3,10}#.

The intersections with the #x#-axis are the points that correspond to #y=0#.
\[\begin{array}{rcl}
-{{x^2}\over{3}}-2\cdot x+7 &=& 0 \\&&\phantom{xxx}\blue{\text{the equation that should be calculated}}\\
x=\dfrac{-{-2}-\sqrt{\left(-2\right)^2-4 \cdot -{{1}\over{3}} \cdot 7}}{2 \cdot -{{1}\over{3}}} &\vee& x=\dfrac{-{-2}+\sqrt{\left(-2\right)^2-4 \cdot -{{1}\over{3}} \cdot 7}}{2 \cdot -{{1}\over{3}}} \\&&\phantom{xxx}\blue{\text{quadratic formula entered}}\\
x=-\sqrt{30}-3 &\vee& x=\sqrt{30}-3 \\&&\phantom{xxx}\blue{\text{calculated}}\\
\end{array}\]
The coordinates of the intersections with the #x#-axis are: #\rv{-\sqrt{30}-3,0}# and #\rv{\sqrt{30}-3,0}#. To draw the point in the graph, we have to write the coordinates as decimal numbers (rounded to 1 decimal). That gives:#\rv{-8.5,0}# and #\rv{2.5,0}#.

The four points in the graph are: #\rv{0,7}#, #\rv{-3,10}#, #\rv{-\sqrt{30}-3,0}# and #\rv{\sqrt{30}-3,0}#.